Answers
to October Puzzlers
The number of
entries in Young Saint Louis.com's Math Puzzler contest
increased during October. But, Question 6 proved to be too
much.
All but one of
the entrants answered that question incorrectly. And, the
one kid with the correct answer to Question 6 missed other
answers.
Several entrants
got five of the six Puzzlers correct.
At first glance,
Question 6 looked pretty easy. But, it turned out to be a
toughie.
Wayne Hesse of
Green Park Lutheran School is our website's Mr. Math Puzzler.
When asked about Question 6, he suggests each contestant look
for a general principle of math before answering a question.
In this case the
math principle says: "You can't average averages."
Question 6 gave
the average speed per hour for each trip segment. But, you
needed to go back to find the time it took the biker to cover
the distance of each segment before giving the answer. (Look
below to see two different ways to answer Question 6. The
answer is 10 kilometers per hour.)
Remember, all
those answering all six Puzzlers correctly will have their
names published the following month. Also, all winning entries
will be put into a hat and up to three $10 Borders book certificates
will be awarded.
Answers
to October, 2001, Math Puzzlers
1. What is the
sum of the spots on the left side of the stack of dice?
Answer: 11
Explanation:
You look at the hidden left side of the dice to find the number
of spots. For future reference, remember the opposite faces
of a six-sided die always add up to seven.
2. What is x?
1+2=5
2+3=13
4+5=41
5+6=61
6+7= x
Answer: 85
Explanation:
The relationship of the other numbers is that both numbers
on the left side of the = signs have been squared first before
they are added.
3. What is the
total of these six fractions?
1/3 + 3/1 + 3/6
+ 6/3 + 4/8 + 8/4 = ?
Answer: 8 1/3
Explanation:
You need to express these fractions with a common denominator
before adding them. The common denominator is 24 and the numerators
then add to 200. When that is divided by 24, you get 8 1/3.
4. Suppose you
have two egg timers, a five-minute and a three-minute. How
can you use these two measuring devices to time an egg that
would be boiled for exactly two minutes?
Answer: Start
both timers at the same time and, when the three-minute timer
goes off, put the egg in boiling water. Then, when the five-minute
timer goes off, it will have been two minutes.
5. Add arithmetical
symbols (+, -, x, (divide symbol) between the numbers on the
left side of the equals sign to make the equation true.
1 2 3 4 5 6 7
8 9 = 100
Answer: 1
+ 2 + 3 + 4 + 5 + 6 + 7 + 8 x 9 =100
Explanation:
Some of you found other combinations using +, - and x to get
to 100.
6. Timothy is
riding a bicycle on a road that can be thought of as having
four equal parts. On the first fourth, which is level, he
pedals at 10 kilometers per hour. On the second fourth, which
is on an upslope, he pedals 5 kilometers per hour. On the
third fourth, a downward slope, he goes 30 kilometers per
hour. On the final fourth, which is level again but with a
tailwind, he goes 15 kilometers per hour. What is Timothy's
average speed?
Answer: 10
kilometers per hour
Explanation:
You can figure this either with arithmetic or with algebra.
With arithmetic
reasoning, pick a common distance for each segment, such as
10 kilometers. Thus, the first segment at an average of 10
kpr takes 1 hour or 60 minutes. The second segment at 5 kpr
takes two hours or 120 minutes. The third segment at 30 kpr
takes just 20 minutes. The fourth segment at 15 kpr takes
40 minutes. That's a total of 240 minutes or four hours. The
number of minutes divided by four (representing the four segments)
is 60 minutes, or 10 kilometers per hour.
With algebra
reasoning, you express that as:
Distance is L.
Total time is
L L L L
--- + --- + --- + ---
10 5 30 15
3L 6L L 2L
-- + -- + -- + --
30 30 30 30
12L
---
30
2L
--
5
distance
Rate = --------
time
(4L)
Rate = ------
(2L/5)
(20L)
Rate = -----
(2L)
Rate = 10