Mr.
Math Puzzler was too tough in October
The number of
entries was up in the Math Puzzler competition in October.
But, for the first time in awhile, there were no entrants
who got all the answers correct.
That's the first
time in several months that Mr. Math Puzzler has stumped all
the entrants.
For awhile, we
thought Mr. Puzzler had gone soft on his questions. But, in
October, he put in some Puzzlers that required educated guessing
and some ingenuity, rather than just established formulas.
In October, we
also started again to get group entries from individual schools.
That must mean
that some of you have been asking your math teachers to give
some extra credit if you enter the Math Puzzler competition.
Wayne Hesse is
our Mr. Math Puzzler. He's an eighth grade teacher at Green
Park Lutheran School in south St. Louis County.
For years, he's
given his math students extra "fun" questions to
finish after their regular assignments are done. In class,
those puzzles might be actual wooden or metal puzzles or they
might be paragraph problems on paper.
His students can
do those extra puzzles for both fun and extra credit.
That's what the
Young Saint Louis.com Math Puzzlers are all about.
Learning math while having fun. And without the pressure of
getting a formal grade.
Be sure to ask
your math teachers if he or she will give extra credit for
entry in the YSL.com competition. We have new questions
every month.
Each month, we
remind new entrants to check out some previous questions and
answers to learn how Mr. Math Puzzler thinks. The Puzzlers
started over two years ago so you have plenty of examples
of both the questions and the answers.
Just click on
to the Past Stories tab at the top of the homepage.
Pick any month after September, 2001, and you'll have examples
of questions and answers. When you are ready for the November,
2003, questions, click here.
Remember, if you
get all six answers correct, we publish your name next month
along with the November answers.
Also, as an added
incentive, we put all entries with six right answers into
a hat. Then, we draw up to three and award $10 Border's book
certificates to them.
The
October Math Puzzlers answers
1. Two towns are
linked by a railroad. Every hour on the hour a train leaves
each town for the other town. The trains all go at the same
speed and every trip from one town to the other takes five
hours. How many trains are met by one train during a one-way
trip?
Answer:
11 trains
The explanation:
Since the trains are traveling toward each other, one train
will meet another every 30 minutes. There are nine 30-minute
points in a five-hour period. Then, there will be one other
train in the depot when our train leaves and another in the
depot at the destination point. That adds to 11 trains met.
2. Timothy spent
all his money in five stores. In each store, he spent $1 more
than half of what he had when he came in. How much did Timothy
have when he entered the first store?
Answer:
$62
The explanation:
The best way to do this is to start at the end of the sales
spree. To be able to have something to spend in the fifth
store, Timothy would need to have had $3. (That's $2 being
half of the amount from the previous store plus the $1 extra.)
Then, we go backwards. He'd have entered the fourth store
with $6 plus the $1 extra or a total of $7. Using this same
pattern, he'd have had $14 plus $1 or $15 in the third store;
then $30 plus $1 of $31. Double the $31 and he started with
$62.
3. How many ways
can you read POP off the diagram below? Letters must touch
each other horizontally, vertically or diagonally. Any P can
be both the first and letter of a single POP? (Hint: Remember,
you can spell backwards as well as use some back-and-forth
spelling.)
P
P
O P
P
O P O P
P
O P
P
Answer:
64
The explanation:
There is no formula for this. But, starting with the P's on
the four peaks of the figure, you can achieve four POPs each
for a total of 16. Then, you can find 8 POPs with the four
mid-line P's or 32. Then, for the center P, you can find 16
other POPs. That's a total of 64.
4. Which three
digits are represented by X, Y and Z in this sum?
XXXX
YYYY
ZZZZ
-----
YXXXZ
Answer:
X=9, Y=1, Z=8
The explanation:
9
9 9 9
1
1 1 1
8
8 8 8
--------
1
9 9 9 8
5. Consider all
the whole numbers from zero through one billion. What is the
sum of all the digits needed to write down these numbers?
Answer:
40,500,000,001
The explanation:
This is a question that uses a very old formula. The way to
find the number of digits in all those numbers is to add the
digits in a series of lines that starts with the first digit
and the digits in the last number before one billion, which
is 999,999,999.
- That looks
like this:
0 + 9 + 9 + 9 + 9 + 9 + 9 + 9 + 9 + 9 + 9 = 81
- The second
pattern is:
1 + 9 + 9 + 9 + 9 + 9 + 9 + 9 + 9 + 9 + 8 = 81
- Continuing,
you find there are 500,000,000 million pairings, all totaling
81 digits.
- Multiply
500,000,000 by 81 and you get 40,500,000,000.
- But, you
need to add one extra digit to represent the final digit
in one billion, thus the answer of 40,500,000,001.
6. In a stable,
there are men and horses. In all, there are 22 heads and 72
feet. How many men and how many horses are in the stable?
Answer:
8 men, 14 horses
The explanation:
You can set up two formulas to represent the two parts to
this question. We'll use M for men and H for horses.
The "head"
quotation: H x M = 22
The "feet"
quotation: 4H + 2M = 72
Then, multiply
the "head" quotation by -2 so we can eliminate one
portion:
-2 (H + M) = -2 (22) becomes -2H - 2M = -44
Then subtract
the "feet" quotation:
-2H
- 2M = -44
4H + 2M = 72
------- ---
2H =
28
-- --
2 2
H
= 14
If there are
14 horses, there have to be 8 men.