We
had a winner in September's Math Puzzlers
Ben Harmon of
St. Louis answered all six Math Puzzlers correctly in the
September math competition. He's a first time winner.
The number of
entries in September increased. That probably means kids were
getting back into a math-mode with the start of school.
After all those
graded math quizzes, Young Saint Louis.com's Math Puzzlers
offer an opportunity to do some math just for fun. And, we
don't even care if you get some help with your answers from
older brothers and sisters.. or even parents, if they can
help.
YSL.com
believes having fun with math--without grading pressure--can
help you learn more about math. And knowing the fundamentals
of math is real important for your future.
The September
puzzlers had a couple tricky questions. In one, there was
no correct answer. We warned you about that. But, there was
also Question 5. There, the time lapse during the first half
of the parade review was one second less than the second half.
The Puzzlers for
October are all word-and-number questions. There are no illustrations.
(To look at the October questions, just click
here.)
Here are the answers
and explanations for the September Puzzlers:
The
Math Puzzlers Answers
(September, 2002)
1. Remove only
one matchstick to make the math correct:
Answer: Change + to -.
The explanation:
The one matchstick that can make the difference is the vertical
one that makes the "plus" sign. If you take off
that matchstick, the "plus" becomes a "minus"
and six (VI) minus (instead of plus) two (II) equals four
(IV).
2. The local bottling
plant recycles old bottles to make new ones at the rate of
10 old bottles to produce one new one. Remarkably, every bottle
the plant produces gets recycled. Starting with 1,000 new
bottles, how many bottles can be made if the bottles are recycled
continually?
Answer: Either 1,111 or 111
The explanation:
Remember, Mr. Math Puzzler was talking about continual recycling.
The first batch of 1,000 bottles will recycle into 100 new
bottles. When those 100 are returned and recycled, they will
add another 10 bottles. Then, on the third recycling circuit,
the 10 bottles will add one more bottle. Depending on whether
you counted the first 1,000 bottles into your total or not,
Mr. Puzzler says the answer could be either 1,000 + 100 +
10 + 1 = 1,111 or 100 + 10 + 1 = 111. He accepts either answer.
3. An entire group
chartered a boat for the day for $840. Unfortunately, one
couple had severe colds and had to cancel, so each person
remaining had to chip in another $35. How many were there
originally?
Answer: 8
The explanation:
There's a trial-and-error way of figuring this. You can divide
the original $840 charter cost by a variety of numbers. You're
looking for a number that, if you subtract one couple, their
share can be made up if each remaining person chips in an
additional $35 each. Eight is a number that fits. Originally,
each of the eight would pay $105 to make up the $840 fee.
Then, if subtracting two, the six remaining would owe a total
of $140, which is $35 more than their original contribution.
4. A messenger
capable of running long distances set out to deliver a message
so that reinforcements could be brought to help fight a horde
of glubs. The messenger had to run for 24 miles. For two-thirds
of the distance, he averaged 8 miles per hour. At what rate
did he have to run the remainder of the distance in order
to average 12 miles per hour for the entire journey?
Answer: No right answer
The explanation:
Remember, Mr. Math Puzzler said there was one question without
a right answer. The reason is the messenger, running at 8
miles per hour, ran two-thirds of the 24-mile distance in
two hours. But, to average 12 miles per hour for the 24 miles,
he would have had to do the whole distance in two hours. At
8 miles per hour, he'd used up the full two hours for just
two-thirds of the distance.
5. An officer
on horseback rides slowly down a line of 60 mounted troops
placed 10 feet apart. Beginning with the first man, the officer
takes 29 seconds to reach the 30th man. At that rate, how
long will it take him to reach the 60th (last) man?
Answer: 59 seconds
The explanation:
This answer is a little tricky. The officer took one second
between each man. But, in the first 30, he actually started
with number 1 so there were just 29 gaps between 1 and 30.
But, in the second 30, there are 30 gaps because of the extra
one from 30 to 31, so the second half took 30 seconds. There
is not gap at the beginning between zero and 1.
6. Thirty-six
coins will buy one knife, one sword and nine arrows. Two swords
can be traded for one knife and four arrows. What is the price
of each item purchased separately?
Answer: knife=2; arrow=3; sword=7
The explanation:
This answer takes quite a bit of figuring. It involves two
formulas and then the use of the subtraction method under
the system of equations.
You know two
things:
- one knife,
one sword and nine arrrows cost 36 coins and
- two swords
can be traded for one knife and four arrows.
| Formula
one: |
36 = k +
s + 9a |
| |
|
| Formula
two: |
2s
= k + 4a |
| Subtract: |
-2s -2s
0 = k - 2s + 4a |
| |
|
| Then Subtract: |
36
= k + s + 9a
- ( 0 = k - 2s + 4a)
36 = 3s + 5a |
Then, we set
up a substitution table for s and see what a and k need to
be:(no fractions here):
|
s
|
a
|
k
|
|
1
|
x
|
|
|
2
|
6
|
x
|
|
3
|
x
|
|
|
4
|
x
|
|
|
5
|
x
|
|
|
6
|
x
|
|
|
7
|
3
|
2
|
Until you
equate 7 coins to one sword, there's no way to solve the second
formula. But, with the 7, 2 swords equals 14 coins and it's
possible to solve assign 3 coins to each arrow and 2 coins
to the knife. Thus
2s (14) = 4a (12) + k (2)
Then you substitute
those numbers to the first formula:
36 coins = k (2) + s (7) +
9a (27)